53. Maximum Subarray
Given an integer array
nums
, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.Example:
Input: [-2,1,-3,4,-1,2,1,-5,4], Output: 6 Explanation: [4,-1,2,1] has the largest sum = 6.
Follow up:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
class Solution {
public:
int maxSubArray(vector<int>& nums) {
int n = nums.size();
if(!n) return 0;
vector<int> dp(n, 0);
int ans = dp[0] = nums[0];
for(int i=1;i<n;++i){
dp[i] = max(dp[i-1], 0) + nums[i];
ans = max(ans, dp[i]);
}
return ans;
}
};
simple dp.
dp[i] --> maxSubString that ends at nums[i].
if dp[i-1] > 0 , which means dp[i] using the maxSubarray before will be greater than only nums[i].
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